Question

You have a balloon containing 3 L of air at STP in a vacuum chamber. What will the volume of the balloon be when you reduce the pressure to 50 kPa and increase the temperature to 450 K?

A) 7.00 L
B) 9.89 L
C) 0.68 L
D) 5.46 L

Answer 1

we can use the combined gas law equation to find volume of gas

`(P1V1)/(T1) = (P2V2)/(T2)`
P - pressure
V - volume
T - temperature
parameters at STP conditions are on the left side and parameters for the second instance are on the right side of the equation
standard temperature is 273 K and standard pressure is 10⁵ Pa
substituting the values in the equation

`( 10^(5)Pa*3L )/(273 K) = (50000Pa*V)/(450K)`
V = 9.89 L
new volume is 9.89 L
answer is B) 9.89 L