Question

What is an equation of a circle with center (5,0) that passes through the point (1,1)

Answer 1

(x-5)2+y2=17
(5,0)=(h,k)
(1,1) =(x,y)
r2=17

Answer 2

The equation of a circle with center (h, k) and radius r is
(x -h)² +(y -k)² = r²

This will be true for the given point, allowing us to find r².
(1 -5)² +(1 -0)² = r² = 17

The desired equation is ...
(x -5)² +y² = 17