Question

I have 2 questions that I need help with. Thank you for helping.

Answer 1

Hello!

The equation for a circle is

(x - a)^2 + (y - b)^2 = r^2

(a,b) is the center of the circle

The equation is going to be

(x + 2)^2 + (y - 10)^2

We have to find the radius

To find this we use the equation


`r = √((xsub2 - xsub1)^2 + (ysub2 - ysub1)^2)`

The sub1's are the center points
The sub2's are a point of a circle

Put in the points


`r = √((-2 + 2)^2 + (10 - 6)^2)`


`r = √(16)`

This shows that the answer is A)
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The equation of a circle is (x - a)^2 + (y - b)^2

This means that the equation will be

(x - 1)^2 + (y - 2)^2 = r^2

Now we find the radius


`r= √((0-1)^2 + (6-2)^2)`

This gives us


`r = √(17)`

This means the answer is C

Hope this helps!

Answer 2

r^2=(x−h)^2+(y−k)^2

(-2, 6) and (-2, 10)

r^2 = (10 - 6)^2 + (-2+2)^2
r^2 = 4^2
r^2 = 16

answer is A.
(x +2)^2 + (y - 6)^2 = 16
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r^2=(x−h)^2+(y−k)^2

(1,2) and (0,6)

r^2 = (6-2)^2 + (0-1)^2
r^2 = 4^2 + 1^2
r^2 = 17

answer is C.
(x - 1)^2 + (y - 2)^2 = 17
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