Question

An ideal gas has a density of 1.25×10−6 g/cm3 at 1.00×10−3 atm and 40.0 ∘c. identify the gas. an ideal gas has a density of 1.25×10−6 at 1.0010 and 40.0 . identify the gas. nitrogen hydrogen oxygen neon chlorine argon

Answer 1

Answer: OXYGEN

Step-by-step explanation:
As density is given as,

d = P M / R T
Solving for M,
M = d R T / P ------ (1)
Data Given:
d = 1.25 × 10⁻⁶ g/cm³ = 0.00125 g/L

R = 0.08206 L.atm.mol⁻¹.K⁻¹

T = 40 °C + 273 = 313 K

P = 1.00 × 10⁻³ atm

Putting values in eq. 1,

M = (0.00125 g.L⁻¹ × 0.08205 atm.L.mol⁻¹.K⁻¹ × 313 K) ÷ 1.0 × 10⁻³ atm

M = 32.10 g/mol

Result:
Molecular Mass of O₂ is 32 g/mol.