Question

Two dice are thrown once. Find the probability of obtaining :

(i) a total of 6
(ii) a total of 10

Answer 1

Total possible outcomes in throwing two dice = 6×6 = 36

(i)The favourable outcomes of the event ", a total of 6" are,
(1,5), (2,4), (3,3), (4,2), (5,1)
Thus, the total number of favourable outcomes = 5


`P = ( Number \: of \: favourable \: outcomes )/( Total \: number \: of \: possible \: outcomes)`

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(ii) The favourable outcomes to the event "a total of 10" are (4,6), (5,5), (6,4)
Thus, the total number of favourable outcomes = 3


`P = ( Number \: of \: favourable \: outcomes )/( Total \: number \: of \: possible \: outcome )`

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