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When finding the margin of error for the mean of a normally distributed population from a sample, what is the critical probability, assuming a confidence level of 86%? 0.14 0.86 0.93 0.99]?
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Aug 3, 2019
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When finding the margin of error for the mean of a normally distributed population from a sample, what is the critical probability, assuming a confidence level of 86%? 0.14 0.86 0.93 0.99]?
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Mahesh Nepal
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Answer:
C
Explanation:
on edge
Philip Brocoum
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Aug 5, 2019
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Philip Brocoum
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C. 0.93 I just toke the test
PatrickCurl
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Aug 9, 2019
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4.06 = 0.19 = 0.29 = 0.86 = 19% 29% 38% 332% 247% 293% 2.98 = 406% 0.81 = 353% 2.93 = 22% 4.61 = 86% 6% 81% 483% 41% 422% 461% 3.35 = 298% 0.68 = 68% FINISH 55% 0.38 = 424% 71% 413% 315% 26% 88% 92% 2.
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A simple random sample of 49 items resulted in a sample mean of 80. Assume a population standard deviation of 14. a) Develop a 86.64% confidence interval about the mean. b) Develop a 97.86% confidence
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