Question

PLEASE HELP What are the zeros of function f(x)=x^2+5x+5 written in simplest radical form?

Quadratic formula: photo

Answer 1

Answer:
Option 3,
`x = (-5 - √(5) )/(2), (-5 + √(5) )/(2)`

Step-by-step explanation:
With a quadratic equation written in ax² + bx + c form, we plug in the coefficients of each variable and the constant included in the equation into the quadratic formula given in your image.

For this equation:
variable a = 1
variable b = 5
constant c = 5

So we plug these values in and simplify where we can.

x = -(5) ± √((5)² - 4(1)(5)) / 2(1)

x = -5 ± √(25 - 20) / 2

At this point, we can eliminate options 1 and 4 because their answers do not start with a negative number. Let's continue simplifying:

x = -5 ± √(5) / 2

There is no further simplification that can be done, therefore x = -5 ± √(5) / 2 are the solutions written in radical form, matching option 3.