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How much power does it take to lift a 5.00 kg mass at a constant speed by 3.00 m in 2.50 s? Unit=W

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The weight/force of the object is F = mg = (5.00 kg)(9.81 m/s^2) = 49.05 N
The work done in moving the object is W = Fd = (49.05 N)(3.00 m) = 147.15 J
The power required to accomplish this work in 2.50 s is P = W/t = 147.15 J / 2.50 s = 58.86 Watts

Power requirement increases with increased weight and increased distance, but decreases with increased time.
User Wouter Bolsterlee
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