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A 2,000 g quantity of C-14 is left to undergo radioactive decay. The half-life of C-14 is approximately 5,700 years. After going trough x half-lives, the sample becomes 125 grams. What is x? A) 22,800 B) 28,500 C) 4 D) 5

User Neysa
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The half-life is the time the sample takes to reduce to half of its original value. If we call
m_0 the initial mass of the sample, this means that after 1 half-life the mass will be
(m_0)/(2), after 2 half-lives the mass will be
(m_0)/(4), and so on..
Therefore, after x half-lives the mass of the sample will be

m= (m_0)/(2^x) (1)
In our problem, the initial mass is
m_0 = 2000 g while the mass after x half-lives is
m=125 g, so by using equation (1) we can find the value of x:

2^x = (m_0)/(m)= (2000 g)/(125 g)=16
From which

x=4
And the correct answer is C).
User Anatolyevich
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