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The rectangle below has an area of 4(x+3) [4 is width, x+3 is length] square units. If the dimensions of the rectangle are doubled, what is the area of the new rectangle in terms of x?
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The rectangle below has an area of 4(x+3) [4 is width, x+3 is length] square units. If the dimensions of the rectangle are doubled, what is the area of the new rectangle in terms of x?

User Cheeken
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Well, we need to double each dimension separately first. 4*2 is 8, and (x+3)*2 is (2x+6), so putting these two together, the area in terms of x is 8(2x+6)
User Tom Opgenorth
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