Answer: The number of moles of carbon dioxide produced are
and the mass of calcium carbonate is 61.6 mg
Step-by-step explanation:
To calculate the moles of carbon dioxide gas, we use the equation given by ideal gas which follows:

where,
P = pressure of the gas = 738.0 mmHg
V = Volume of the gas = 15.5 mL = 0.0155 L (Conversion factor: 1 L = 1000 mL)
T = Temperature of the gas =
![25^oC=[25+273]K=298K](https://img.qammunity.org/2019/formulas/chemistry/high-school/vrqkyyitu3rpnlky8usokrw46hqm7gl9o0.png)
R = Gas constant =

n = number of moles of carbon dioxide gas = ?
Putting values in above equation, we get:

For the given chemical equation:

By Stoichiometry of the reaction:
1 mole of carbon dioxide gas is produced from 1 mole of calcium carbonate
So,
of carbon dioxide will be produced from =
of calcium carbonate
- To calculate the mass for given number of moles, we use the equation:

Molar mass of calcium carbonate = 100 g/mol
Moles of calcium carbonate =

Putting values in above equation:

Converting this into milligrams, we use the conversion factor:
1 g = 1000 mg
So,

Hence, the number of moles of carbon dioxide produced are
and the mass of calcium carbonate is 61.6 mg