Question

In ΔABC, ∠CAD = 22° and segment CB = 15 cm. If the cos of 22° = 0.9272, then the sin of ∠C = _______.

-0.9272
0.9272
0.6537
-0.6537

Answer 1

Your answer is B. 0.9272. Hope I was able to help!

Answer 2

Option B. 0.9272

Explanation:

In the given triangle ABC, ∠CAD = 22° segment CB = 15 cm.

We have to find sin of ∠C.

In the given triangle ADC,

∠CAD + ∠ADC + ∠DCA = 180

22° + 90° + ∠DCA = 180

∠DCA = 180 - 112 = 68°

Now we have to get the value of sinC or sin of angle DCA

Therefore sinC = sin 68° = 0.9272

Option B. 0.9272 is the correct option.