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What radius of a circle is required to inscribe an equilateral triangle with an area of 270.633 cm2 and an altitude of 21.65 cm? (round to nearest tenth)
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What radius of a circle is required to inscribe an equilateral triangle with an area of 270.633 cm2 and an altitude of 21.65 cm? (round to nearest tenth)

User Raees Iqbal
by
6.0k points

2 Answers

4 votes

Answer:

r = 14.4

Explanation:

User Hallodom
by
6.3k points
6 votes
Area of an equilateral triangle=(sqrt(3)/4)x^2=270.633
x^2=270.633/[sqrt(3)/4]
x^2=625
x=25
thus the length of equilateral is 25 cm
thus the radius will be given by:
r=25/sqrt(3)=14.43 cm

User Quasiben
by
5.7k points
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