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4 votes
In Miami, the number of highway accidents increased by 20% over a four year period. How many accidents were there in 2013 if there were 5,120 in 2009?

2 Answers

6 votes
.20 x 5,120 = 1024        1024 + 5120 = 6144 
User Erloewe
by
5.7k points
5 votes
We can model this scenario by using the exponential growth formula and plugging in values we know:


A = P(1+r)^(t)

A, the resulting amount, is unknown
P, the principle (starting) amount, is 5120
r, the rate at which P increases, is .05 (if a .2 increase spans over 4 years, there is a .05 increase each year)
t, the amount of time that has passed, is 4

The equation now looks like this:


A = 5120(1.05)^(4)

To find A, we just need to simplify the other side:


A = 6223.392

In 2013, there were ~6224 Miami highway accidents (I rounded up because the amount was more than 6223, and you can't have a fraction of a car accident).
User RDV
by
6.9k points
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