Question

Consider the reaction cacn2 + 3 h2o → caco3 + 2 nh3 . how much caco3 is produced if 47.5 moles nh3 are produced? 1. 0.950 g 2. 9500 g 3. 0.238 g 4. 23.8 g 5. 4750 g 6. 2380 g

Answer 1

The CaCO3 produced if 47.5 moles of NH3 produced is calculated as follows

CaCN2 +3H2O = CaCO3 + 2NH3

by use of mole ratio between CaCO3 to NH3 which is 1:2 the moles of CaCO3 is therefore = 47.5 /2= 23.75 moles

mass of CaCO3 is therefore = moles x molar mass
= 23.75 moles x 100g/mol= 2375 grams which is approximate 2380 grams(answer 6)