Question

Is more energy required to melt one gram of ice at 0 or to boil one gram of water at 100?

Answer 1

The energy required to melt one gram of ice at 0 degrees is given by:

`Q=m L_f`
where m is the mass of the ice and
`L_f = 334 J/g` is the latent heat of fusion of ice. Substituting, we find

`Q=(1g)(334 J/g)=334 J`

The energy required to boil one gram of water at 100 degrees is given by:

`Q=m L_e`
where m is the mass of the water and
`L_e = 2265 J/g` is the latent heat of evaporation of the water. Substituting, we find

`Q=(1 g)(2265 J/g)=2265 J`

Therefore, it is required more energy to boil one gram of water at 100 degrees than to melt one gram of ice at 0 degrees.