Question

A 8.5 v battery supplies a 1.5 ma current to a circuit for 4.0 h .

part a

how much charge has been transferred from the negative to the positive terminal?

Answer 1

The current is defined as the amount of charge that flows through the circuit in a certain time interval:

`I= (Q)/(\Delta t)`
where
I is the current
Q is the charge

`\Delta t` is the time interval

In our problem, the current is
`I=1.5 mA=1.5 \cdot 10^(-3) A` and it runs for a time of

`\Delta t= 4.0 h =14400 s`
so we can use the previous equation to find the charge transferred from one terminal to the other terminal of the battery during this time:

`Q=I \Delta t= (1.5 \cdot 10^(-3) A)(14400 s)=21.6 C`