A 7.100 L sample of gas is cooled from 73.0 °C to a temperature at which its volume is 5.700 L. What is this new temperature? Assume no change in pressure of the gas.

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asked Aug 23, 2019 119k views

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Lunguini · Answer 1 · 2019-08-30T04:50:19+0000

The mew temperature of a sample of gas is calculated using Charles law formula

that is v1/T1 = V2/T2
V1= 7.100 L
T1=73 + 273 = 346 K
V2 = 5.700 L
T2=?

by making the T2 the subject of the formula
T2 =V2T1/V1

T2= 5.700 x 346/7.100 =277.8 K

A 7.100 L sample of gas is cooled from 73.0 °C to a temperature at which its volume is 5.700 L. What is this new temperature? Assume no change in pressure of the gas.

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