Question

A sample of oxygen gas (O2) has a temperature of 273 K at 1.00 atm. What should the density of this gas be? Show all of the work used to find your answer.

Answer 1

According to Ideal Gas Equation,

P V = n R T
Also,
n = mass / M.mass
So,
P V = (mass × R × T) ÷ M.mass
Or,
P × M.mass = (mass × R × T) ÷ V
Since,
Density = mass / volume
So,
P × M.mass = Density × R × T
Or,
Density = (P × M.mass) ÷ (R × T)
Putting Values,

Density = (1.0 atm × 32 g/mol) ÷ (0.0821 L.atm.mole⁻¹.K⁻¹ × 273 K)

Density = 1.42 g/L