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4 votes
Find the volume of a square pyramid with base edges of 48 cm and a slant

height of 26 cm.
A.
11,520 cm3

B.
23,040 cm3

C.
7,680 cm3

D.
768 cm3

2 Answers

3 votes
Firstly, write the stuffs you already know.

Length = Width = 48, Slant Height = 26.
You need to find Height of the pyramid.

Using Pythagoras Theory:
h = ✓26^2 - (48/2)^2
h = 10

Now apply the pyramid volume formula;
Volume = (Length×Width×Height)/3
Thus, v = (48^2 × 10)/3
v = 7680 cm^3
User Cory Ginsberg
by
7.3k points
4 votes

Answer:

Option C is the correct answer.

Explanation:

Let the base edge be b, slant height be s and perpendicular height be h.

We have


s^2=h^2+\left ( (b)/(2)\right )^2

Here s = 26 cm and b = 48 cm

Substituting


26^2=h^2+\left ( (48)/(2)\right )^2\\\\h^2=100\\\\h=10cm


\texttt{Volume of square pyramid, }V=(1)/(3)b^2h

Substituting


V=(1)/(3)* 48^2* 10=7680cm^3

Option C is the correct answer.

User Mirza Delic
by
7.5k points