Question

A 2 kg object moves in a circle of radius 4 m at a constant speed of 3 m/s. a net force of 4.5 n acts on the object. what is the angular momentum of the object with respect to an axis perpendicular to the circle and through its center?

Answer 1

L = 24 kg*m^2/s

Step-by-step explanation:

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Answer 2

The angular momentum of an object moving by uniform circular motion is given by:

`L=mvr`
where
L is the angular momentum
m is the mass of the object
v its velocity
r the radius of the circular orbit.

In our problem, m=2 kg, v=3 m/s and r=4 m, so the angular momentum of the object is

`L=mvr=(2 kg)(3 m/s)(4 m)=24 kg m/s`