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Find the value of k such that the equation (k+4) x^2 + 2(k+1)x +(k-1)= 0 has equal roots

User CBreeze
by
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1 Answer

4 votes

Answer:

b^2-4ac(formula for finding the roots )

Explanation:

1)9-4k=0

k=9/4(roots are real )

2)4-4k+4=0

8-4k=0

k=2(the roots are real )

3)64-8k=0

k=8

4)36-16k+16=0

52-16k=0

k=52/16=13/8

16-4k+4=0

k=5

Explanation:

User Bbonamin
by
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