Question

Someone please answer this!

Answer 1

`4x^2 + 3 = -12x`


`4x^2 + 12x + 3 = 0`

Apply quadratic formula:


`x = (-b \pm √(b^2 - 4ac) )/(2a)`


`x = (-(12) \pm √((12)^2 - 4(4(3))) )/(2(4))`


`x = -2.72 \ or \ -0.28`



`\boxed {\boxed{\text{Answer: x = -2.72 or -0.28 } }}`