Question

C an anyone solve this 3(2b + 3)2 = 36
and if so what is it

Answer 1

Assuming it's linear:

3(2b+3)2 = 36

6(2b+3) = 36
12b + 18 = 36
12b = 18
b = 1.5

Assuming you meant to put the 2 as an exponent:
3(2b+3)² = 36

First do the exponent:
3(4b² + 12b + 9) = 36

Multiply it out:
12b² + 36b + 27 = 36
12b² + 36b - 9 = 0

Factor:
3(4b² + 12b - 3) = 0

Apply Quadratic Formula:

x = (-12 +- √(144 + 48)) / 8
x = (-12+√192) / 8 and x = (-12 - √192) / 8

This makes it so that the variable you're solving for = .232 and -3.232.

Answer 2

`3(2b + 3)^2 = 36`

Divide by 3 on both sides:

`(2b + 3)^2 = 12`

Square root both sides:

`2b + 3= \pm √(12)`

Take away 3 from both sides:

`2b= \pm √(12) - 3`

Divide by 2 on both sides:

`b= ( √(12) -3 )/(2) \ or \ b= ( -√(12) -3 )/(2)`

Answer:

`b= 0.23 \ or \ -3.23`