Question

How many moles of KCl will be produced from 89.0 g of KClO3

Answer 1

Hello there!

The chemical equation for the decomposition reaction of KClO₃ is the following one:

2KClO₃ → 2KCl + 3O₂

For determining the moles of KCl produced from 89,0 g of KClO₃ we are going to use the following conversion factor to go from grams of KClO₃ to moles of KCl:


`89,0g* (1 mol KClO_3)/(122,55 g KClO_3)* (2 moles KCl)/(2 moles KClO_3)=0,726 moles KCl`

So, 0,726 moles of KCl are produced.

Have a nice day!