Question

Determine the Celsius temperature of 2.08 moles of gas contained in a 1.00 L vessel at a pressure of 177 kPa. -183 Incorrect: Your answer is incorrect. °C

Answer 1

we can use the ideal gas law equation to find the temperature,
PV = nRT
where
P - pressure - 177 kPa
V - volume 1.00 x 10⁻³ m³
n - number of moles - 2.08 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature
substituting these values in the equation
177 x 10³ Pa x 1.00 x 10⁻³ m³ = 2.08 mol x 8.314 Jmol⁻¹K⁻¹ x T
T = 10.2 K
temperature in celsius - 10.2 -273 = - 262.8 °C