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​$9500 is​ invested, part of it at 10​% and part of it at 7​%. For a certain​ year, the total yield is ​$nbsp 842.00. How much was invested at each​ rate?

How much was invested at 10​% ​? ​$
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1 Answer

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$5900 was invested at the 10% rate.

To solve this problem, you have to write then solve a system of equations.

Let x be the amount at 10% and y be the amount at 7%.

We can write the following 2 equations.

x + y = 9500
0.1x + 0.07y = 842

Now, you can solve the equations by elimination, substitution or graphing.
Either way, the solution is (5900, 3600).
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