Question

What is the area of this figure

Answer 1

`\text{Total area}=\text{A}_{\text{parallelogram}}+\text{A}_{\text{triangle}}\\\\ \text{A}_{\text{parallelogram}}=\text{base }*\text{ height}=20*16=320\;\text{in}^2\\\\ \text{A}_{\text{triangle}}=\frac{\text{base}*\text{height}}{2}=(8*16)/(2)=(128)/(2)=64\text{ in}^2\\\\ \text{Total area}=320+64=384\text{ in}^2`