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Where is the hole for the following function located f(x)= x+3/(x-4)(x+3)

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In a rational function, holes are located where f(x) is undefined(the denominator is 0), but the undefined points can be factored out. In f(x), when x is 4 or -3, f(x) is undefined. But, x+3 can be factored out, so it is a hole. The hole is located at (-3,-1/7)
User Jguerinet
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2 votes
the hole is located at x=-3
User Mishkin
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