Answer:
The pressure at Mombasa is 101.396 KPascal.
Step-by-step explanation:
Given: Reading on barometer = 760 mm
= 0.76 m
Density of mercury = 1.36 x
kg/
In this case, the pressure can be expressed as:
P = σhg
Where: σ is the density of mercury, h is height of mercury in the barometer, and g is the acceleration due of gravity.
But, g = 9.81 m/
So that,
P = 1.36 x
x 0.76 x 9.81
= 101396.16 Pascal
P = 101.395 KPascal
The pressure at Mombasa is 101.396 KPascal.