Question

3^(4x-5) = (1/27)^(2x+10) show your work

Answer 1

3^4x-5=1/27^2x+10

We move all terms to the left:

3^4x-5-(1/27^2x+10)=0

Domain of the equation: 27^2x+10)!=0

x∈R

We get rid of parentheses

3^4x-1/27^2x-10-5=0

We multiply all the terms by the denominator

3^4x*27^2x-10*27^2x-5*27^2x-1=0

Wy multiply elements

81x^6-270x^2-135x^2-1=0

We do not support expression: x^6

Explanation: