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a softball diamond is a square 60 ft on a side. what is the length from home to second base? (using pythagorean theorem)
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a softball diamond is a square 60 ft on a side. what is the length from home to second base? (using pythagorean theorem)

User Joru
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1 Answer

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60^2 + 60^2 = SH(or c^2) (second to home)

60^2 = 3600 +3600 = 7200

take sqrt of 7200 you get 84.85

therefor the distance from second to home is 84.85 ft
User DaneSoul
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