23.8k views
5 votes
Find an equation for the plane that is perpendicular to the line l(t) = (2, 0, 9)t + (3, −1, 1) and passes through (9, −1, 0).

1 Answer

4 votes
The plane will have its normal vector equal to the direction vector of the line (2, 0, 9). Its equation is
2x +9z = (2, 0, 9)•(9, -1, 0)
2x +9z = 18
User Michel Fernandes
by
8.3k points

No related questions found