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Find an equation for the plane that is perpendicular to the line l(t) = (2, 0, 9)t + (3, −1, 1) and passes through (9, −1, 0).
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Find an equation for the plane that is perpendicular to the line l(t) = (2, 0, 9)t + (3, −1, 1) and passes through (9, −1, 0).

User Jersey Bean
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1 Answer

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The plane will have its normal vector equal to the direction vector of the line (2, 0, 9). Its equation is
2x +9z = (2, 0, 9)•(9, -1, 0)
2x +9z = 18
User Michel Fernandes
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