Question

A train leaves boston at 2:00 pm. a second train leaves the same city in the same direction at 6:00 pm. the second train travels 48mph48⁢mph faster than the first. if the second train overtakes the first at 11:00 pm, what is the speed of each of the two trains?

Answer 1

`\boxed {\boxed { \text {Distance = Speed x Time}}}`

First Train:
Time taken = 9 hours (2pm to 11pm)
Let the speed be x
Distance = Time x Speed = 9x

Second Train:
Time taken = 5 hours (6pm to 11pm)
Speed = x + 48
Distance = Time x Speed = 5(x + 48)

Since both the distance they traveled are the same, we equate the distance to solve for x.

Solve for x:
9x = 5(x + 48)
9x = 5x + 240
4x = 240
x = 60

Find the speed:
x = 60 mph
x + 48= 108 mph

Answer: The spend of the two trains are 60 mph and 108 mph.