76.6k views
1 vote
Find the indicated limit, if it exists. limit of f of x as x approaches 9 where f of x equals x plus 9 when x is less than 9 and f of x equals 27 minus x when x is greater than or equal to 9

The limit does not exist.
18
0
9

Find the indicated limit, if it exists. limit of f of x as x approaches 9 where f-example-1
User Krp
by
7.3k points

2 Answers

5 votes

Answer:

18

Explanation:

User Peter Saxton
by
9.1k points
1 vote

Answer:

B. 18

Explanation:

For the function


f(x)=\left\{\begin{array}{l}x+9,\ \ x<9\\27-x,\ \ x\ge 9\end{array}\right.

we can find the value of the function for all x that are very close to 9 but are less than 9 and for all values of x that are very close to 9 but are greater than 9.

1. For
x<9:


\lim \limits_(x\rightarrow 9)f(x)=\lim \limits_(x\rightarrow 9)(x+9)=9+9=18

2. For
x\ge 9:


\lim \limits_(x\rightarrow 9)f(x)=\lim \limits_(x\rightarrow 9)(27-x)=27-9=18

So, limit exists and is equal to 18.

User Titanous
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories