Question

Given ABC with A(0, 0), B(2, 3),
and C(4,0), prove ABC is isosceles

Answer 1

Explanation:

1. if to calculate the length of AB; AC and BC, then:

`|AB|=√((2-0)^2+(3-0)^2) =√(13).`

`|AC|=√((4-0)^2+(0-0)^2) =4.`

`|BC|=√((2-4)^2+(0-3)^2)= √(13).`

2. if to compare the calculated lengths, then:

AB=BC. It means the given triangle is isosceles.