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40 votes
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I need help on this question I need the answer only :)-example-1
User Arttronics
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1 Answer

14 votes
14 votes

Step 1

Given;

Step 2


\sqrt[3]{48y^4}=2y\sqrt[3]{6y}
\begin{gathered} 14(2y\sqrt[3]{6y})=28y(\sqrt[3]{6y}) \\ 17y(\sqrt[3]{6y}) \end{gathered}

Thus;


17y(\sqrt[3]{6y})-28y(\sqrt[3]{6y})=-11y(\sqrt[3]{6y)}

Answer;

I need help on this question I need the answer only :)-example-1
I need help on this question I need the answer only :)-example-2
User Tomacco
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