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Which shows the following expression after the negative exponents have been eliminated? xy^-6/x^-4 y^2, x=/0 y=/0

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The expression would be
(x^5)/(y^8) after the negative exponents have been removed.

A negative exponent basically tells us to "flip" the side of the fraction it's on. This means that y⁻⁶ on the numerator would go to the denominator, and that x⁻⁴ on the denominator would go to the numerator. This gives us:


(x* x^4)/(y^2* y^6)=(x^5)/(y^8)
User JuFo
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4 votes

It would be B, xx4 y2y6

User MariaJen
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