Question

a cylindrical salt shaker has a radius of 2 cm and a height of 7 cm. It comes in a box that is 8 cm tall and has a square base with an edge length of 4cm. which is closest to the volume of air in the box outside the salt shaker.

Answer 1

we know that

[volume of a cylindrical salt shaker]=pi*r²*h
r=2 cm
h=7 cm
[volume of a cylindrical salt shaker]=pi*2²*7---> 87.92 cm³

[volume of the box]=b²*h
b=4 cm
h=8 cm

[volume of the box]=4²*8---> 128 cm³

[the volume of air in the box outside the salt shaker]=128-87.92--> 40.08 cm³

the answer is
the volume of air in the box outside the salt shaker is 40.08 cm³