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A box that has a mass of 80 kg slides down a ramp with a 30 degree angle. The free-body diagram shows the forces acting on the box. Ignoring friction and air resistance, what is the acceleration of the box, to the nearest tenth? Answer choices are 0.5 m/s2 4.9 m/s2 8.5 m/s2 9.8 m/s2

2 Answers

4 votes
the first one I believe
User Atish Shimpi
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2 votes

Answer:

a= 4.9
(m)/(s^(2) )

Step-by-step explanation:

Force equation


F= m*a


F= W*g*sen (30)\\F= 80 kg * 9.8 (m)/(s^(2) ) * sen (30)\\F= 80 kg * 9.8 (m)/(s^(2) ) * 0.5\\F= 392  *(kg*m)/(s^(2) ) = 392 N


a= (F)/(m) = (392 N)/(80 kg) = (392 (kg*m)/(s^(2) ) )/(80 kg)\\ a= 4.9 (m)/(s^(2) )

User Fwalch
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