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If Logx (1 / 8) = - 3 / 2, then x is equal to

User Cogitovita
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If the equation written like this

log x^{ (1)/(8) } = - (3)/(2) then 10^{- (3)/(2) } = x^{ (1)/(8) } (10^{- (3)/(2) })^(8) = ( x^{ (1)/(8) } )^(8) x= 10^(-3*4) = 10^(-12) x=10^(-12) If the equation looks like this , then it has the solution x=10^(-12)

User RamiReddy
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