Question

What value of n makes the equation true? (2x^9y^n)(4x^2y^10)=8x^11y^20

Answer 1

N=10

Explanation:

On edg 2020 :)

Answer 2

Hi there! The answer is n = 10.


`(2 {x}^(9) {y}^(n) )(4 {x}^(2) {y}^(10) ) = 8 {x}^(11) {y}^(20)`

As you see at the powers of x, we need to add the exponents of the power we when multiply them.

`{x}^(9) * {x}^(2) = {x}^(9 + 2) = x {}^(11)`

The powers of y work the same way.

`{y}^(n) * {y}^(10) = {y}^(n + 10) = {y}^(20)`

Hence, n = 10, since

`{y}^(10 + 10) = {y}^(20)`