Question

Write an exponential equation in the form y = abx whose graph passes through points (0, 2) and (1, 1.3)

Answer 1

substitute it into eq 2 and solve for a:
25 = ab^2
25 = a(10/a)^2
25 = a(100/a^2)
25 = (100/a)
a = 100/25
a = 4
.
substitute it into eq 1 and solve for b:
10 = ab
10 = 4b
10/4 = b
2.5 = b write an exponential equation y=ab^x whose graph passes through these points
(1,10), (2,25)
Hope this helps! ~Nadia~
From:(1,10)
10 = ab^1
10 = ab (equation 1)
and from:(2,25)
25 = ab^2 (equation 2)
.
solve equation 1 for b:
10 = ab
10/a = b

Answer 2

ANSWER

The required exponential equation is


`y= 2{(0.65)}^(x)`


Step-by-step explanation

Let the equation of the exponential equation be


`y = a( {b}^(x) )`


Since the graph passes through


`(0,2)`

it must satisfy its equation.


We substitute to obtain,


`2= a( {b}^(0) )`


This simplifies to,


`2= a( 1)`


This simplifies to,


`a = 2`

We substitute this value into the equation to get,



`y = 2( {b}^(x) )`
We apply the second point to find the value of b.


Since the graph passes through

`(1,1.3)`

it must also satisfy its equation.


This means that,


`1.3= 2( {b}^(1) )`


This implies that,


`1.3= 2b`

We divide both sides by 2 to get,


`b = 0.65`


We substitute b back into the equation to get,



`y= 2{(0.65)}^(x)`