The sides of the cubes are numbered 1 through 6. if they are both tossed, what is the probability that they will both be a 3? A 1/3 B 1/6 C 1/36

Question

asked Jan 10, 2019 24.1k views

2 Answers

PaulBinder · Answer 1 · 2019-01-15T07:19:44+0000

Answer: Option 'C' is correct.

Explanation:

Since we have given that

the sides of the cubes are numbered 1 through 6,

So,

$P(\text{ getting a 3})=(1)/(6)$

if they are both tossed ,

Probability (getting that they will both be a 3) is given by

$=(1)/(6)* (1)/(6)\\\\=(1)/(36)$

(∵
$\\P(\text{A and B})=P(A\cap B)=P(A).P(B)\\$ )

Therefore, Option 'C' is correct.