Question

How many moles of chromium(iii) nitrate are produced when chromium reacts with 0.85 moles of lead(iv) nitrate to produce chromium(iii) nitrate and lead?

Answer 1

The moles of chromium (iii) nitrate produced is calculated as follows

write the equation for reaction

3 Pb(NO3)2 + 2 Cr = 2 Cr(NO3)3 + 3 Pb

by use of mole ratio between Pb(NO3)2 to Cr(NO3)3 which is 3 : 2 the moles of Cr(NO3)3 is therefore
= 0.85 x2 /3 = 0.57 moles