Question

Determine the chemical formula for the compound, diaquadicarbonylzinc tetrabromopalladate(iv).

Answer 1

`[Zn(H_2O)_2(CO)_2][PdBr_4]`

Step-by-step explanation:

Hello,

In this case, one could build-up the formula, via analyzing the name as follows:

- It says tetrabromopalladate (IV), it means that it is a mixed anion, composed by four bromine atoms (tetrabromo) and one palladium atom due suffix ate), therefore the anion is
`[PdBr_4]`.

- By means of the cation, it starts by diaqua, so it has two
`H_2O` as an aquocation. Next, is says dicarbonyl, so two carbonyl groups
`C=O` are bonded as well. Finally, the metallic part is given by the presence of zinc, so the cation turns out as
`[Zn(H_2O)_2(CO)_2]` by complexity.

Therefore, the resulting formula is:
`[Zn(H_2O)_2(CO)_2][PdBr_4]`

Best regards.

Answer 2

Missing question:
A. [PdZn(H2O)2(CO)2]Br4.
B. [Zn(H2O)2(CO)2]2[PdBr4].
C. [Pd(H2O)2][Zn(CO)2]Br4.
D. [Pd(H2O)2]2[Zn(CO)2]3Br4.
E. [Zn(H2O)2(CO)2][PdBr4].
Answer is: E. [Zn(H2O)2(CO)2][PdBr4]..
In this complex diaqua means two waters (H₂O), dicarbonyl means two carbonyl groups (CO), zinc(Zn) and palladium (Pd) are central atoms or metals, bromine has negative charge -1. Bromine, water and carbonyl are ligands.