Question

I need help with this please

Answer 1

`(1)/(5) (2x - 10) + 4x = -3 ( (1)/(5)x + 4)`

Apply distributive property to distribute 1/3 and -3:


`(2)/(5) x - 2 + 4x = - (3)/(5)x - 12`

Sort all the x to the left and the constants to the right:


`(2)/(5) x + (3)/(5)x + 4x = - 12 + 2`

Simplify:


`5x = -10`

Divide by 5:


`x = -2`



`\boxed { \boxed {\text {Answer: x = -2}}}`

Answer 2

1/5(2x - 10) + 4x = -3(1/5x + 4)
0.4x - 2 + 4x = -0.6x - 12
4.4x - 2 = -0.6x - 12
5x - 2 = -12
5x = -10
x = -2