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What volume of 12.0 M HCL is needed to contain 3.00 moles of HCL

What volume of 12.0 M HCL is needed to contain 3.00 moles of HCL
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What volume of 12.0 M HCL is needed to contain 3.00 moles of HCL

User Thmsnhl
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1 Answer

7 votes
solution: 12 M HCL= 3 mol HCL/x
answer: 0.250 L
User Whaledawg
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