Register
An Ellipse is centered at (0,0) if the equation of the ellipse is 14x^2+4y^2=196 find the equation of the ellipse in standard form and the vertiesOf both the major and minor axis
93.2k views
4 votes
An Ellipse is centered at (0,0) if the equation of the ellipse is 14x^2+4y^2=196 find the equation of the ellipse in standard form and the vertiesOf both the major and minor axis

User Amit Sinha
by
6.2k points

2 Answers

4 votes

14 x^(2) +4 y^(2) = 196
(14 x^(2) )/(196) + (4y)/(196) = 1

( x^(2) )/(14) + ( y^(2) )/(49) = 1 To find Major Axis we have to find biggest denominator, it is 49. The major axis is on the y-axis. 49=a^2, a=7, Center (0,0). Vertices of major axis =(0,0+a) and (0,0-a) Vertices of major axis(0,-7), (0,+7) Minor axis is on the x-axis. b^2=14, b= √(14) Vertices of minor axis (- √(14), 0), ( √(14) , 0)
User Girish Kolari
by
7.1k points
4 votes

Answer:

C edge2020

Explanation:

An Ellipse is centered at (0,0) if the equation of the ellipse is 14x^2+4y^2=196 find-example-1
User Nyteshade
by
6.1k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

7.3m questions

9.7m answers

Other Questions

How do you estimate of 4 5/8 X 1/3
Write words to match the expression. 24- ( 6+3)
Please solve the following equation. x-6x=56
whats the most accurate estimation of 65+77
Find the additive inverse of 18/23
Link Copied!