Question

The current in a coil with a self inductance of 1.5 mH increases from 0 to 1.0 A in a tenth of a second. What is the induced emf in the coil

Answer 1

the induced emf in the coil is 15 mV.

Step-by-step explanation:

Given;

self inductance, L = 1.5 mH = 1.5 x 10⁻³ H

change in current = dI = 1.0 A

change in time, dt = 1/10 = 0.1

The induced emf is calculated as;

`Induced \ EMF = L ((dI)/(dt) )\\\\Induced \ EMF = 1.5 * 10^(-3)\ ((1)/(0.1) )\\\\Induced \ EMF = 1.5 * 10^(-3) \ * \ 10\\\\Induced \ EMF = 15 * 10^(-3) \ V\\\\Induced \ EMF = 15 \ mV`

Therefore, the induced emf in the coil is 15 mV.